10.2 Derivatives of sums

Let’s suppose we have a function f(x)=q(x)+r(x)f(x)=q(x)+r(x), then the derivative of f(x)f(x) is 66 6 Note that this relies on the property that the limit of two things added together is the same as the sum of the limits of the two things limxa(z(x)+q(x))=limxaz(x)+limxaq(x)\lim_{x\to a}(z(x)+q(x))=\lim_{x\to a}z(x)+\lim_{x\to a}q(x) Where z(x)z(x) and q(x)q(x) are any functions of xx whose limit is defined as xax\to a.

dfdx\displaystyle\frac{df}{dx} =limh0f(x+h)f(x)h\displaystyle=\lim_{h\to 0}\frac{f(x+h)-f(x)}{h} (10.11)
=limh0q(x+h)+r(x+h)q(x)r(x)h\displaystyle=\lim_{h\to 0}\frac{q(x+h)+r(x+h)-q(x)-r(x)}{h} (10.12)
=limh0q(x+h)q(x)+r(x+h)r(x)h\displaystyle=\lim_{h\to 0}\frac{q(x+h)-q(x)+r(x+h)-r(x)}{h} (10.13)
=limh0q(x+h)q(x)h+limh0r(x+h)r(x)h\displaystyle=\lim_{h\to 0}\frac{q(x+h)-q(x)}{h}+\lim_{h\to 0}\frac{r(x+h)-r(x% )}{h} (10.14)
=dqdx+drdx\displaystyle=\frac{dq}{dx}+\frac{dr}{dx} (10.15)

That is to say that

ddx(a(x)+b(x))=ddx(a)+ddx(b)\frac{d}{dx}(a(x)+b(x))=\frac{d}{dx}(a)+\frac{d}{dx}(b) (10.16)